28s^2-53s+24=0

Solution for 28s^2-53s+24=0 equation:

28s^2-53s+24=0

a = 28; b = -53; c = +24;
Δ = b2-4ac
Δ = -532-4·28·24
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-53)-11}{2*28}=\frac{42}{56}
=3/4
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-53)+11}{2*28}=\frac{64}{56}
=1+1/7
$